Question

Calculate strength in shear of 16mm diameter of bolt of grade 4.6 for lap joint

(a) 50 kN

(b) 40 kN

(c) 29 kN

(d) 59 kN

This question was posed to me in class test.

Origin of the question is Bolted Connections in portion Bolted Connections of Design of Steel Structures

Answer 1

The correct answer is (c) 29 kN

To explain I would say: Bolts will be in single shear. Diameter of bolt = 16mm. Net area = 0.78x(π/4)x16^2=156.83mm^2.

Strength of bolt in shear = Anbfub/(√3 x 1.25) = 156.83x400x10^-3/1.25x√3 = 28.97kN.