The correct answer is (b) 4
For explanation I would say: Fo=0.7fubAnb=0.7x800x0.78x(π/4)x20^2x10^-3=137.22 kN
Assume μf=0.5, ne=1, kh=1
Slip resistance of bolt = μf ne kh Fo/1.25 = 0.5x1x1x137.22/1.25 =54.88 kN
Number of bolts required = 200/54.88 = 3.64 = 4(approximately).