Correct answer is (c) s = (2/ sinφ)(Mfr/fywtw)^0.5
Explanation: The anchorage length of tension field is s = (2/ sinφ)(Mfr/fywtw)^0.5 where φ = inclination of tension field = tan^-1(d/c), c is spacing between stiffeners, d is depth of beam, Mfr is reduced plastic moment capacity of the respective flange plate, fyw is yield stress of web and tw is thickness of web. The anchorage length should be less than or equal to spacing between stiffeners.