Right option is (a) d
Best explanation: When both inputs are same then the o/p is high for a XNOR gate.
i.e., A B O/P
0 0 1
0 1 0
1 0 0
1 1 1.
Thus, it will produce 1 when inputs are even number of 1s or all 0s, and produce 0 when input is odd number of 1s.