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How many address bits are required to select memory location in the Memory decoder?

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How many address bits are required to select memory location in the Memory decoder?

(a) 4 KB

(b) 8 KB

(c) 12 KB

(d) 16 KB

This question was posed to me during an online interview.

My question is taken from Programmable Logic Array in division Memory Devices of Digital Circuits

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Best answer
Correct option is (c) 12 KB

To elaborate: Memory decoder decodes the memory to be selected for a specific address. Since the given EPROM and RAM are of 4 KB (4 * 1024 = 4096) capacity, it requires 12 address bit to select one of the 4096 memory locations.

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