Question

The minimum distance Dmin can also be given as

(a) Dmin >= α + β + 1

(b) Dmin <= α + β + 1

(c) Dmin >= α + β – 1

(d) Dmin <= α + β + 1

The question was posed to me in quiz.

Query is from Error Detecting and Correcting Capability and Sampling in section Channel Coding of Digital Communications

Answer 1

Right answer is (a) Dmin >= α + β + 1

Easiest explanation: If a code can correct α errors and detect β errors, then the minimum distance can be given by the relation Dmin >= α + β + 1.