Question

After digitization process a digital image with M rows and N columns have to be positive and for the number, L, max gray levels i.e. an integer power of 2 for each pixel. Then, the number b, of bits required to store a digitized image is:

(a) b=M*N*k

(b) b=M*N*L

(c) b=M*L*k

(d) b=L*N*k

I have been asked this question in a job interview.

My enquiry is from Representing Digital Images topic in section Digital Image Fundamentals of Digital Image Processing

Answer 1

The correct answer is (a) b=M*N*k

Easiest explanation: In digital image of M rows and N columns and L max gray levels an integer power of 2 for each pixel. The number, b, of bits required to store a digitized image is: b=M*N*k.