Question

For pixels p(x, y), q(s, t), the city-block distance between p and q is defined as:

(a) D(p, q) = [(x – s)^2 + (y – t)^2]^1/2

(b) D(p, q) = |x – s| + |y – t|

(c) D(p, q) = max (|x – s| + |y – t|)

(d) None of the mentioned

I got this question by my college director while I was bunking the class.

My question is from Relationship between Pixels and Image Enhancement Basics topic in division Image Enhancement of Digital Image Processing

Answer 1

Right choice is (b) D(p, q) = |x – s| + |y – t|

For explanation: The city-block distance for pixels p(x, y), q(s, t) is the D4 distance given by:

D(p, q) = |x – s| + |y – t|.