Right option is (b) 2(0.5)^nu(n)
To explain I would say: By applying the z-transform on both sides of the difference equation given in the question we obtain,
\(\frac{Y(z)}{X(z)}=\frac{2}{1-0.5z^{-1}}\)=H(z)
By applying the inverse z-transform we get h(n)=2(0.5)^nu(n).