Correct choice is (c) ck= 1/TP(X(kF0))
The best I can explain: Let us consider a signal x(t) whose Fourier transform X(F) is given as
X(F)=\(\int_{-∞}^∞ x(t)e^{-j2πF_0 t}dt\)
and the Fourier series coefficient is given as
ck=\(\frac{1}{T_p} \int_{-∞}^∞ x(t)e^{-j2πkF_0 t}dt\)
By comparing the above two equations, we get
ck=\(\frac{1}{T_p} X(kF_0)\)