The correct option is (b) Mlog2M
The explanation is: Since we will compute the convolution via the FFT, let us consider the circular convolution of the N point sequence g(n) with an M point section of h(n) where M>N. In such a case, we know that the first N-1 points contain aliasing and that the remaining M-N+1 points are identical to the result that would be obtained from a linear convolution of h(n) with g(n). In view of this, we should select a DFT of size M=L+N-1. Thus the total number of complex multiplications to be performed are Mlog2M.