Correct answer is (d) 0.3*10^-38
Best explanation: Let the mantissa be represented by 23 bits plus a sign bit and let the exponent be represented by 7 bits plus a sign bit.
Thus, the smallest floating point number that can be represented using the 32 bit number is
(1/2)*2^-127=0.3*10^-38
Thus, the smallest floating point number that can be represented using the 32 bit number is
(1-2^-23)*2^127=1.7*10^38.