Right choice is (a) True
Best explanation: The analog filter in the time domain is governed by the following difference equation,
\(\sum_{K=0}^N a_K y^K (t)=\sum_{K=0}^M b_K x^K (t)\)
Taking Laplace transform on both the sides of the above differential equation with all initial conditions set to zero, we get
\(\sum_{K=0}^N a_K s^K Y(s)=\sum_{K=0}^M b_K s^K X(s)\)
=> Heq(s)=Y(s)/X(s)=\(\frac{\sum_{K=0}^M b_K s^K }{\sum_{K=0}^N a_K s^K}\).