The solution of the linear congruence 4x = 5(mod 9) is?
(a) 6(mod 9)
(b) 8(mod 9)
(c) 9(mod 9)
(d) 10(mod 9)
The question was asked by my college professor while I was bunking the class.
This intriguing question comes from Applications of Number Theory in chapter Number Theory and Cryptography of Discrete Mathematics