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How many numbers of three digits can be formed with digits 1, 3, 5, 7 and 9?

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How many numbers of three digits can be formed with digits 1, 3, 5, 7 and 9?

(a) 983

(b) 120

(c) 345

(d) 5430

The question was asked during an internship interview.

This intriguing question originated from Counting in chapter Counting of Discrete Mathematics

1 Answer

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Best answer
Correct option is (b) 120

The explanation is: Here number of digits, n = 5 and number of places to be filled-up r = 3. Hence, the required number is ^5P3 = 5!/2!*3! = 120.

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