Right answer is (d) ^13C9
To explain: For this type of problem, n>=r must be true and so according to stars and bars model, the number of possible arrangements of stars and bars is n-1Cr-1 or equivalently, there are ^n-1Cr-1 distributions of n identical objects into r distinct non-empty bins. In this example, there are n = 14 identical objects to be distributed among r=10 distinct bins. Using the above formula, the number of possible distributions is ^13C9.