Question

If two 14-sided dice one is red and one is blue are rolled, find the probability that a 3 on the red die, a 5 on the blue die are rolled.

(a) \(\frac{4}{167}\)

(b) \(\frac{3}{197}\)

(c) \(\frac{5}{216}\)

(d) \(\frac{1}{196}\)

This question was posed to me during an interview for a job.

My enquiry is from Multiplication Theorem on Probability in section Discrete Probability of Discrete Mathematics

Answer 1

The correct option is (b) \(\frac{3}{197}\)

The best explanation: Using the rule of product, there are 196 possible combinations of rolls. Since having the red die = 3 and the blue die = 5 are one of the 196 combinations, the required probability is \(\frac{1}{14}*\frac{1}{14} = \frac{1}{196}\).