The correct option is (b) Y transpose is nilpotent
The explanation: Suppose, we have a matrix
\(a=\begin{bmatrix}
1 & 0\\
2 & 1\\
\end{bmatrix} \)
then Y^2 will not resulting in Y, hence it is not idempotent, Y^2 is not 0 and so it is not nilpotent. But, as Y is a square matrix, by the property inverse will exist in this case.