Right answer is (d) 8
To explain I would say: E = √2πfrNΦ, Φ = flux per pole = 4/pBplr
dimensions are doubled ⇒ l^1 = 2l and r^1 = 2r ⇒ Φ^1 = 4Φ
No. of turns doubled ⇒ N^1 = 2N, fr changes only when the poles are changed ⇒ fr^1 = fr
⇒ E^1=√2πfr(2N)(4Φ) = 8E
The generated voltage will change by a factor of 8.