For a local enhancement using mean and variance, there is one condition: σs(x, y) ≤ k2DG, where, MDG is global standard deviation, k2 a positive constant and σs(x, y) a measure of contrast at point (x, y). Then, which fact is true for k2 if its values is less than 1.0?

Question

For a local enhancement using mean and variance, there is one condition:

Answer 1

For local enhancement using mean and variance, the condition is:

The variance in the local region must be sufficiently high to apply meaningful enhancement.

Explanation:

• Mean: The local mean adjusts the brightness by calculating the average pixel intensity in a given neighborhood.
• Variance: The local variance measures how much the pixel intensities deviate from the mean, indicating the amount of contrast or texture within the region.

Condition:

• High Variance: Effective enhancement is typically applied to regions where the variance is high, as these regions contain more detail (e.g., edges, textures). Low variance indicates smooth, uniform regions where enhancement might not be beneficial or could lead to noise amplification.

In summary, local enhancement using mean and variance works best when the variance is sufficiently high, ensuring that enhancement focuses on regions with sufficient contrast or texture.