The correct choice is (c) ln(7)∞∑n=0 x^n+1/7^n+1
The best explanation: We know that ∫1/7−x dx=−ln(7−x) and there is a power series representation for 1/7−x. So, ln(7−x)=−∫1/7−xdx
=−∫ ∞∑n=0 x^n/7^n+1dx=C
⇒ ∞∑n=0 x^n+1/7^n+1
So, the answer is, ln(7−x)=ln(7)∞∑n=0 x^n+1/7^n+1.