The correct answer is (a) by reducing secondary turns
Best explanation: In a P.T., at no load, we get
where, R is the ratio error
n is the turns ratio
Is is the secondary winding current
Ie is the iron loss component
Im is the magnetising component
From the above equation it is seen that to reduce the ratio error, actual ratio and nominal ratio must be made equal. This can be done by reducing the secondary turns.