Question

What is the electric field intensity at a distance of 20cm from a charge 2 X 10^-6 C in vacuum?

(a) 250,000

(b) 350,000

(c) 450,000

(d) 550,000

The question was asked in an interview for internship.

This intriguing question comes from Electric Field Intensity in section Electrostatic Fields of Electromagnetic Theory

Answer 1

Correct option is (c) 450,000

Explanation: E = Q/ (4∏εor2)

= (2 X 10^-6)/(4∏ X εo X 0.2^2) = 450,000 V/m.