Question

Find the potential of V = 60sin θ/r^2 at P(3,60,25)

(a) 5.774

(b) 6.774

(c) 7.774

(d) 8.774

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This is a very interesting question from Electric Potential in division Electrostatic Fields of Electromagnetic Theory

Answer 1

The correct answer is (a) 5.774

Explanation: V = 60sin θ/r^2, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/3^2 = 5.774 volts.