For a local enhancement using mean and variance, there is one condition: σs(x, y) ≤ k2DG, where, MDG is global standard deviation, k2 a positive constant and σs(x, y) a measure of contrast at point (x, y). Then, which fact is true for k2 if its values is greater than 1.0?

Question

For a local enhancement using mean and variance, there is one condition:

Answer 1

For local enhancement using mean and variance, the condition is:

The variance in the local window should be greater than a threshold value for enhancement to be applied.

Explanation:

1. Mean: The local mean calculates the average intensity of pixels in a neighborhood.

2. Variance: The local variance measures the spread of intensity values around the mean. A high variance indicates that the pixels in the neighborhood have a wide range of intensity values, suggesting features like edges or textures. A low variance indicates that the region is smooth or uniform, which may not benefit from enhancement.

Condition:

• Variance Threshold: The local enhancement algorithm enhances areas where there is significant texture or contrast, i.e., where the variance is high. If the variance is low, enhancement might not be applied because the area lacks distinct features.

This condition ensures that enhancement is applied where it can improve image features (high variance regions), while leaving uniform regions (low variance regions) unaffected or minimally enhanced.