Question

Find the ratio of refractive index of medium 2 to that of medium 1, when the Brewster angle is 60 degree.

(a) 0.707

(b) 1.5

(c) 0.866

(d) 1.732

I have been asked this question in semester exam.

This is a very interesting question from Brewster Angle in section EM Wave Propagation of Electromagnetic Theory

Answer 1

Right option is (d) 1.732

For explanation I would say: The tangent of the Brewster angle is the ratio of the medium 2 permittivity to the medium 1 permittivity. Thus tan θb = (n2/n1). Given that θb = 60 degree, the ratio n2/n1 will be tan 60 = 1.732.