Question

The propagation constant of a wave with attenuation and phase constant given by 2 and 3 respectively is

(a) 2 – 3j

(b) 3 – 2j

(c) 2 + 3j

(d) 3 + 2j

I had been asked this question in examination.

This key question is from Transmission Line Secondary Parameters topic in division Transmission Lines of Electromagnetic Theory

Answer 1

Right answer is (c) 2 + 3j

The explanation: The propagation constant is given by γ = α + jβ. Given that α = 2 and β = 3. Thus we get the propagation constant as γ = 2 + 3j.