Right answer is (a) 25.8 mV
Explanation: The thermal voltage of the diode is given by, VT = KT/q, by substituting the values of T, K which is Boltzmann constant and q which is the charge of the electron we get VT = (300*1.38*10^-23)/ (1.602*10^-19), VT= 25.8mV.