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A speech signal has a total duration of 20 sec. It is sampled at the rate of 8 kHz and then PCM encoded. The signal-to-quantization noise ratio is required to be 40 dB. The minimum storage capacity needed to accommodate this signal is

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A speech signal has a total duration of 20 sec. It is sampled at the rate of 8 kHz and then PCM encoded. The signal-to-quantization noise ratio is required to be 40 dB. The minimum storage capacity needed to accommodate this signal is

(a) 1.12 KBytes

(b) 140 KBytes

(c) 168 KBytes

(d) None of the mentioned

This question was posed to me by my school teacher while I was bunking the class.

This key question is from Digital Transmission in portion EDC Overview of Electronic Devices & Circuits

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The correct option is (b) 140 KBytes

Explanation: (SNR)q = 1.76 + 6.02(n) = 40 dB, n = 6.35

We take the n = 7.

Capacity = 20 x 8k x 7 = 1.12 Mbits = 140 Kbytes.

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