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Identify the correct condition for a semiconductor to be electrically neutral.

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Identify the correct condition for a semiconductor to be electrically neutral.

(a) Nd+p=Na+n

(b) Nd-p=Na+n

(c) Nd+p=Na-n

(d) Nd-p=Na-n

I have been asked this question in an interview for job.

My question is from Charge Densities in a Semiconductor impurities topic in chapter Conduction in Semiconductors of Electronic Devices & Circuits

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Correct option is (a) Nd+p=Na+n

The explanation: The sum of the number of donors and the holes is equal to the sum of the number of the acceptors and the electrons.

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