Question

A full wave rectifier supplies a load of 1KΩ. The AC voltage applied to diodes is 220V (rms). If diode resistance is neglected, what is the ripple voltage?

(a) 0.562V

(b) 0.785V

(c) 0.954V

(d) 0.344V

The question was posed to me in an interview for internship.

Enquiry is from Full-wave Rectifier topic in portion Application of Diodes of Electronic Devices & Circuits

Answer 1

The correct answer is (c) 0.954V

The explanation is: The ripple voltage is  (Vϒ)RMS=ϒVDC /100.

VDC=0.636*VRMS* √2=0.636*220* √2=198V and ripple factor ϒ for full wave rectifier is 0.482.

Hence, (Vϒ)RMS=0.482*198 /100=0.954V.