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A shunt capacitor of value 500µF fed rectifier circuit. The dc voltage is 14.43V. The dc current flowing is 200mA. It is operating at a frequency of 50Hz. What will be the value of peak rectified voltage?

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A shunt capacitor of value 500µF fed rectifier circuit. The dc voltage is 14.43V. The dc current flowing is 200mA. It is operating at a frequency of 50Hz. What will be the value of peak rectified voltage?

(a) 18.67V

(b) 16.43V

(c) 15.98V

(d) 11.43V

This question was posed to me in an international level competition.

The doubt is from Capacitor Filters topic in portion Application of Diodes of Electronic Devices & Circuits

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The correct answer is (b) 16.43V

The best I can explain: We know, Vm=Vdc+Idc/4fC

=14.43+ {200/ (200*500)} 10^3

=14.43+2=16.43V.

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