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The base emitter voltage in a cut off region is _________

(a) greater than 0.7V

(b) equal to 0.7V

(c) less than 0.7V

(d) cannot be predicted

I got this question in an interview for job.

I need to ask this question from Transistor Switching Times in chapter Transistor Characteristics of Electronic Devices & Circuits

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Correct choice is (c) less than 0.7V

Easiest explanation: From the cut off characteristics, the base emitter voltage (VBE) in a cut off region is less than 0.7V. The cut off region can be considered as ‘off mode’. Here, VBE < 0.7 and IC=0. For a PNP transistor, the emitter potential must be negative with respect to the base.

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