Question

For a half-wave rectifier having diode voltage VD and supply input of VI, the diode conducts for π – 2Θ, where Θ is given by

(a) tan^ -1 VD/VI

(b) tan^-1  VD/VI – VI

(c) sin^-1  VD/VI

(d) sin^-1  VD/VI – VI

The question was asked in a national level competition.

My enquiry is from Rectifiers topic in section Diodes of Electronic Devices & Circuits

Answer 1

Right choice is (c) sin^-1  VD/VI

For explanation I would say: The diode doesn’t conducts when VD ≥VI . Hence Θ = sin^-1  (D/VI).