Question

Calculate LC for a full wave rectifier which provides 10V dc at 100mA with a maximum ripple of 2%. Input ac frequency is 50Hz.

(a) 40*10^-6

(b) 10*10^-6

(c) 30*10^-6

(d) 90*10^-6

I got this question in an interview for job.

I'm obligated to ask this question of L-Section Filter topic in chapter Application of Diodes of Electronic Devices & Circuits

Answer 1

The correct choice is (a) 40*10^-6

To explain: LC=1/6√2ω^2ϒ

ω=2πf=314

By putting the values, LC=1/6√2(314)^2 0.02=40*10^-6.