Question

The correct relation between the emitter current Ie and the base current Ib is given by

(a) Ib = (1 + α) Ie

(b) Ib = (α – 1) Ie

(c) Ie = (1 – ß) Ib

(d) Ie = (1 + ß) Ib

I had been asked this question by my college director while I was bunking the class.

This is a very interesting question from BJTs Current-Voltage Characteristics in section Bipolar Junction Triodes (BJTs) of Electronic Devices & Circuits

Answer 1

Correct choice is (d) Ie = (1 + ß) Ib

Easy explanation: The correct mathematical expression are Ie = (1 – ß) Ib and Ib = (1 – α) Ie respectively.