Question

For the circuit shown, find the quiescent point.

(a) (6V, 1mA)

(b) (4V, 10mA)

(c) (10V, 3mA)

(d) (3mA, 10V)

This question was posed to me in an interview for job.

My question is from Problems on AC and DC Analysis in portion Small-Signal Low-Frequency AC models of Transistors of Electronic Devices & Circuits

Answer 1

Right choice is (c) (10V, 3mA)

Explanation: We know, hoe=12V

(IC)SAT =VCC/RL=12/6K=2mA. IB=10V/0.5M=20µA. IC= βIB=1mA. I

hoe=VCC-ICRL=12-1*6=6V. So, quiescent point is (6V, 1mA).