Right answer is (a) VCE < VCC / 2
To explain I would say: Thermal runaway is a growing process which can ultimately harm the transistor due to unnecessary internal heating or increase in ambient temperature. It occurs due to increase in collector current ahead of the maximum specified value. Additionally, it also occurs due to excessive internal power dissipation above the maximum allowed value. Thermal runaway can be disallowed by maintaining the provision of thermal stability in addition to the treatment of heat sink.
According to thermal stability condition, VCE should be less than Vcc/2 results in the Q-point operation at a safe level. On the contrary, if the location of Q-point is at VCE > Vcc/2, then the transistor is more likely to get damaged due to thermal runaway.