Question

In a half wave rectifier, the sine wave input is 50sin50t. If the load resistance is of 1K, then average DC power output will be?

(a) 3.99V

(b) 2.5V

(c) 5.97V

(d) 6.77V

This question was posed to me during a job interview.

Enquiry is from Half-Wave Rectifier in section Application of Diodes of Electronic Devices & Circuits

Answer 1

Correct option is (b) 2.5V

For explanation: The standard form of a sine wave is Vmsinωt. BY comparing the given information with this equation, Vm =50.

Power=Vm^2/RL=50*50/1000=2.5V.