Question

When the contributing structure contains the same number of two-electron bonds as the normal lewis formula, it will be __________

(a) Heterovalent hyperconjugation

(b) Sacrificial hyperconjugation

(c) Isovalent hyperconjugation

(d) All of the mentioned

I have been asked this question in an interview for internship.

I want to ask this question from Hyperconjugation in division Reactivity of Molecules Reaction Mechanism of Engineering Chemistry I

Answer 1

Right answer is (c) Isovalent hyperconjugation

To explain: When the contributing structure contains the same number of two-electron bonds as the normal lewis formula, it will be isovalent hyperconjugation.