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A point is 8 units away from the vertical plane and 2 units away from profile plane and 4 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the side view and front view of point is _______________

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A point is 8 units away from the vertical plane and 2 units away from profile plane and 4 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the side view and front view of point is _______________

(a) 12 units

(b) 6 units

(c) 10 units

(d) 8 units

The question was posed to me in an international level competition.

My doubt is from Projection of Points in First Quadrant in division Projection of Points of Engineering Drawing

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Best answer
The correct choice is (c) 10 units

The best explanation: Since the point is 2 units away from the profile plane the distance from the point to reference line will be 2 units. And then the point is at a distance of 8 units from the vertical plane the distance from reference line and point will be 8, sum is 10.

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