Question

A point is 2 m away from the vertical plane and 1 m away from profile plane and 9 m away from horizontal plane in 3rd quadrant then the projections are drawn on paper the distance between the side view and top view of point is _____________

(a) 21

(b) 14.86

(c) 11.4

(d) 10.4

This question was posed to me during an interview for a job.

Origin of the question is Projection of Points in Third Quadrant topic in division Projection of Points of Engineering Drawing

Answer 1

The correct option is (b) 14.86

Easiest explanation: Since here distance from side view and top view is asked for that we need  the distance between the front view and side view (1+9); front view and top view (9+2)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √(10^2+11^2 ) =14.86 m.