Right choice is (c) ^180⁄π tan^-1(5)
The explanation is: For the transformed function to have a Rolles point is equivalent to the existing function having a Lagrange point somewhere in the real number domain, we are finding
the point in the domain of the original function where we have f'(x) = tan(α)
Let the angle to be rotated be α
We have
f'(x) = 9x^2 + 5 = tan(α)
9x^2 = tan(α) – 5
For the given function to have a Lagrange point we must have the right hand side be greater than zero, so
tan(α) – 5 > 0
tan(α) > 5
α > tan^-1(5)
In degrees we must have,
α^deg > ^180⁄π tan^-1(5).