Correct answer is (b) lies between -1 and 0
Easiest explanation: limx → 0 [x]Cos(x)
We know that,
x-1 < [x] < x
Multiplying by Cos(x), we get
(x-1)Cos(x) < [x]Cos(x) < xCos(x)
Taking limits, we get
limx → 0 [(x-1)Cos(x)] < limx → 0 [x]Cos(x) < limx → 0[xCos(x)]
=> -1 < limx → 0 [x]Cos(x) < 0.