Right option is (d) \(\frac{4}{3} πa^3 \)
To explain I would say: The equation of a circle is x^2 + y^2 = a^2
When it is revolved about x-axis, the volume is given as
\(V = 2 \int_a^b πy^2 dy\)
\(= 2 \int_0^a π(a^2-x^2) dx\)
\(= 2π \Big(a^2 x – \frac{x^3}{3}\Big)_0^a\)
\(= \frac{4}{3} πa^3.\)