Right choice is (b) 2
Easiest explanation: zz̅+ω\(\overline{\omega}\)=100⇒|z|^2+|ω|^2=100, also, since |z|, |ω|∈I^+, therefore, (|z|,|ω|)=(8,6) or (6,8). Hence, |z+ω|≥||z|-|ω||=|8-6|=2.