The correct option is (d) Left and right limits are not equal and hence it is not differentiable
For explanation: f(x)=(x+5), if x>-5 and f(x)=-(x+5), if x≤-5
Since the break is at x=-5, we calculate the limit at this point.
We know that, a function is not differentiable at point x=a, if either \(\lim_{h \to 0}\frac{f(a+h)-f(a)}{h}\)does not exist or is infinity. We check limits for both the cases of the function.
Left limit: Here, a=-5.
\(\lim_{h \to 0}\frac{f(-5+h)-f(-5)}{h}\)
\(\lim_{h \to 0}\frac{-(-5+h+5)-(-(-5+5))}{h}\)
=-1
Right limit: Here, a=1.
\(\lim_{h \to 0}\frac{f(1+h)-f(1)}{h}\)
\(\lim_{h \to 0}\frac{(1+h+5)-(1+5)}{h}\)
=1
Since the two limits are not equal, the function is not differentiable.