The correct choice is (c) \(z=ax+e^\frac{-a}{α} y+c\)
Easiest explanation: Given: \(q= e^\frac{-p}{α}\)
The given equation does not contain x, y and z explicitly.
Setting p = a and q = b in the equation, we get \(b= e^\frac{-p}{α}.\)
Hence, a complete solution of the given equation is,
z=ax+by+c, with \(b= e^\frac{-a}{α}\)
\(z=ax+e^\frac{-a}{α} y+c.\)