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A force vector is along 4i – 4k direction and has a magnitude 100N and another force vector is along 4i +2j -4k and has a magnitude of 120N. What is the resultant of both forces?

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A force vector is along 4i – 4k direction and has a magnitude 100N and another force vector is along 4i +2j -4k and has a magnitude of 120N. What is the resultant of both forces?

(a) 80i + 40j – 80k N

(b) 80i – 40j – 80k N

(c) 151i + 40j – 80k N

(d) 151i+ 40j – 151k N

This question was addressed to me in examination.

The question is from Cartesian Vectors in portion Force Vectors of Engineering Mechanics

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Correct answer is (d) 151i+ 40j – 151k N

The best explanation: Just make the unit vectors of the given directions of the vectors and then multiply them with their respective magnitudes, after than you will get two vectors in the Cartesian form. Just add them.

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