In the calculations of the moment of inertia of the area about an inclined axis, we have some transformation done. They are:
(a) Iu = Ix cos2θ + Iysin2θ – 2Ixycosθsinθ
(b) Iv = Ixcos2θ + Iysin2θ – 2Ixycosθsinθ
(c) Iu = Ixcos2θ + Iysin2θ – 2Ixycosθsinθ
(d) Iv = Ixcos2θ + Iysin2θ + 2Ixycosθsinθ
I had been asked this question during an online interview.
This interesting question is from Moments of Inertia for an Area About Inclined Axis in division Moments of Inertia of Engineering Mechanics